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  • Stroke(mm)
  • Max. Absorbed Energy(J)
  • Equivalent Mass(kgf)
  • Max. Resisting Force Value(N)
  • Piston Rod Return Force(N)
  • Max. Absorbed Energy (per Minute)(J/min)
  • Thread Size M
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    • MISUMI

    Shock Absorbers Compact Fixed

    Shock Absorbers Compact Fixed

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    Part number:

    Still undefined. 5 possible part numbers found.
    Quantity:

    Outline drawing and specifications table

    Dimensional Drawing

    MAMKS
    [ ! ] Operating ambient temperature: -5 to 70°C
    [ ! ] Collision Velocity Range: 0.3 to 1 m/s
    [ ! ] Max. operating cycle: 60 cycle/min
    [M]Material: Free Cutting Steel
    [S] Surface Treatment: Electroless Nickel Plating
    ·Caps, nuts, etc., are not sold separately.

    Specification Table

    Part Number
    MAMKS2508
    Part NumberThread Dia.StrokeMaximum Absorbed Energy (E')Maximum Equivalent Mass
    (me')
    (kg)    		Piston Rod
    Return Force
    (N)    		Max.
    Drag Value
    (N)    		(L1)d1fB
    (Wrench Flats)    		T
    TypeNo.M × PSPer cycle
    (J)    		Per minute
    (J)
    MAMKS1406M14 × 1.564.510080152,000404219.6 (17)6
    1606M16 × 1.55.5130120202,700521.9 (19)
    2008M20 × 1.588.82007014.73,4304761.527.7 (24)8
    2508M25 × 1.513.730011021.65,390837 (32)10
    2708M27 × 1.519.635015023.57,350
    * Each item in the specification table represents the following.
    • [Maximum Drag Value]The maximum value of the hydraulic resistance force that occurs during energy absorption (during stroke).
    • [Maximum Absorbed Energy]The maximum amount of energy that the absorber can receive at one time. (More than this will lead to damage)
    • [Equivalent Mass]The mass when the total energy to be absorbed by the absorber is equivalent to the kinetic energy in horizontal motion.
      It is "a value that converts selected factors such as thrust, the amount of collision material, and velocity into mass."
    • [Piston Return Force]This is the spring force that causes the piston to return from its pushed position.

    Selection Supporting Information

    ■Oil shock absorber is a shock absorber that
    primarily uses oil. Compared with other cushioning materials (rubber, spring, air, etc.), they are compact and capable of repeatedly absorbing large impact energy
    softly without rebound. Internal structure and basic principle of oil type shock absorbers are shown as follows.
    When an object collides with a piston rod, the oil in the pressure chamber is compressed by a piston.
    　The clearance between inner tube and piston is so small that compressed oil is forced out of the orifices.
    　At this point, the impact energy is converted into heat energy by dynamic resistance.

    The piston rod sinks into the shock absorber body so that the oil equal in volume to the piston
    moves into the accumulator.
      This mechanism provides an ideal shock absorbing action.
    Various absorption characteristics can be obtained depending on the number and size of orifices.
    (Refer to classification according to absorption characteristics structures.)
    Please note that when the wrong collision speed is selected, some abnormal reaction may occur during collision or the impact energy may not be absorbed in an ideal manner.
    　　
    ■Procedure of Selection
    (1) Calculation of inertial energy (E1 ) 
    According to examples of calculation for selection, calculate inertial energy based on collision mass (m), collision velocity (V)
    ·moment of inertia (I) and collision angular velocity (ω).

     

    (2) Calculation of additional energy (E2') 
    Confirm whether there is propulsion (F) or not and calculate the
    additional energy according to Examples Of Calculation For Selection.

     

    (3) Temporary decision of absorber stroke 
    Obtain the temporary stroke (S') based on Fig. 1.

     

    (4) Calculation of total energy 
    Calculate the total energy from the sum of inertial energy (E1) and additional energy (E2 ').

     

    (5) Select absorption characteristics structures from energy ratio 
    Select an orifice type from Fig. 2 temporarily.

     

    (6) Check max. absorbed energy per minute 
    Calculate the energy (ET) per minute from the operating cycle (cycle/min) and total energy, and confirm whether or not the value is within the possible operati ng range.

     

    (7) Check equivalent mass 
    According to examples of calculation for selection, calculate the equivalent mass and confirm whether it is less than the max. equivalent mass in the catalog (me').
    　

     

     

    Calculate the temporary stroke S' with the Inertial Energy E1 (Adjustable / Fixed Force Type)

     

    Fig. 2 Select the orifice type from energy ratio (additional energy E2' / inertial energy E1)
    Examples of Calculation for Selection
    Selection examples: Pure inertia collision (Horizontal collision without thrust)
    Selection examples: Horizontal collision with air cylinder thrust force
    Selection examples: Non-thrust stop when cylinder descends
    App. Example
    and
    Collision Conditions

    [Collision Conditions]
    m = 25 kg
    V = 0.6 m/s
    F=ON
    N = 30 times/min


    Air Cylinder
    Inner diameter ø40 Operating pressure 0.5 MPa

    [Collision Conditions]
    m = 30 kg
    V = 0.6 m/s
    N = 20 times/min

    [Collision Conditions]
    m = 15 kg
    V = 0.2 m/s
    N = 10 times/min

    Air Cylinder
    Inner diameter ø25 Operating pressure 0.5 MPa

    Collision Velocity V
    [m/s]
    		V = 0.6 m/sV = 0.6 m/s

    V = 0.2 m/s

    * Collision velocity V is actual measurements
    or 1.5 to 2 times the average speed

    Absorbed Energy

    Moment of Inertia
    Energy
    E1

    [J]
    		E1 = m × V22 = 25 × 0.622 = 4.5 JE1 = m × V2 2 = 30 × 0.62 2 = 5.4 JE1 = m × V2 2 = 15 × 0.22 2 = 0.3 J
    Temporary stroke S'
    [mm]
    		From Figure 1, S' = 20 mm (Select adjustable type)From Figure 1, S' = 15 mm (Select adjustable type)From Figure 1, S' = 10 mm (Select adjustable type)
    Additional
    Energy
    E2
    [J]
    		E2’ = 0JThrust of the cylinder is F = 628.4N
    E2' = F × S' = 628.4 × 0.015 = 14.8 J    		Cylinder thrust is F = 245.4 N
    E2' = (F + mg) × S' = (245.4 + 15 × 9.8) × 0.01 = 3.92 J
    Total energy E'
    [J]
    		E’ = E1+E2’ = 4.5+0 = 4.5JE’ = E1+E2’ = 5.4+9.4 = 14.8JE’ = E1+E2’ = 0.3+3.92 = 4.22J
    Equivalent Mass
    me'
    [kg]
    		me' = 2 × E' V2 = 2 × 4.5 0.62 = 25 kgme' = 2 × E' V2 = 2 × 14.8 0.62 = 82.2 kgme' = 2 × E' V2 = 2 × 4.22 0.22 = 211 kg
    Tentative selection
    		Select Adjustable Type
    Select L from the collision velocity.
    Select MAC1612 from E and me'

    (stroke
    S = 12 mm)
    		Select Adjustable Type
    Select medium speed M from the collision velocity.
    Select MAC2016M from E and me'

    (stroke
    S = 16 mm)
    		Select Adjustable Type
    Select ultra low speed S from Fig. 2.
    Select MAC1612S from E and me'

    (stroke
    S = 12 mm)
    Recalculation
    		E2 = 0J
    E = E1+E2 = 4.5J    		me = 2 × E V2 = 25 kgE2+F × S=10.1J
    E = E1+E2 = 15.5J    		me = 2 × E V2 = 86.1 kgE2 + (F + mg) × S = 4.71 J
    E = E1+E2 = 0.3+4.71=5.01J    		me = 2 × E V2 = 250 kg
    Energy per minute ET
    		ET = E × N = 4.5 × 30 = 135 J/minET = E × N = 15.5 × 20 = 310 J/minET = E × N = 5.01 × 10 = 50.1 J/min
    Confirmation
    		E, me, N, and ET are all OK
    Select MAC1612L    		E, me, N, and ET are all OK
    Select MAC2016M    		E, me, N, and ET are all OK
    Select MAC1612S
    * For pure-inertial collision without thrust force, select the orifice type by only collision velocity.
    Examples of Calculation for Selection
    Selection examples: Horizontal collision with belt conveyor thrust force
    Selection examples: Collision with synchronous motor driven load
    Selection examples: Horizontal rotation collision with torque
    App. Example
    and
    Collision Conditions


    Dynamic Friction Coefficient µ = 0.4

    [Collision Conditions]
    m = 5 kg
    V = 0.5m/s
    N = 20 times/min


    Motor output P = 20 w,
    Number of poles M = 36
    Power Supply Frequency f = 50 Hz　
    Reduction ratio K = 20

    [Collision Conditions]
    m = 1 kg
    R=0.4 m
    r = 0.3 m
    θ=20°
    N = 10 times/min
    l = 43mr2
    3 mr2 = 0.12 kg·m2
    ω = 5.6 rad/s
    F=59.3 N

    [Collision Conditions]
    I = 125.5 kg·m2
    ω = 1.8 rad/s
    R=1.25 m
    N = 6 times/min
    T=68.6 N⋅m

    Collision Velocity V
    [m/s]
    		V = 0.5m/sV = Rω = 0.40 × 5.6 = 2.24 m/sV = Rω = 1.25 × 1.8 = 2.25 m/s
    Absorbed Energy
    Moment of Inertia
    Energy
    E1
    [J]
    		E1 = m × V22 = 5 × 0.522 = 0.625 JE1=Iω22=0.12 × 5.622=1.88JE1=Iω22=125.5 × 1.822=203.31J
    Temporary stroke S'
    [mm]
    		From Figure 1, S' = 5 mm (Select adjustable type)From Figure 1, S' = 10 mm (Select adjustable type)From Figure 1, S' = 50 mm (Select adjustable type)
    Additional
    Energy
    E2
    [J]
    		F = µmg = 0.4 × 5 × 9.8 = 19.6 N
    E2’ = F·S’ = 19.6 × 0.005 = 0.098J    		E2' = (F + mg) × S' = (59.3 + 1 × 9.8) × 0.01 = 0.69 JE2’=TR·S’=68.61.25 × 0.05=2.74J
    Total energy E'
    [J]
    		E’ = E1+E2’ = 0.625+0.098 = 0.723JE’ = E1+E2’ = 1.88+0.69 = 2.57JE’ = E1+E2’ = 203.31+2.74 = 206.05J
    Equivalent Mass
    me'
    [kg]
    		me' = 2 × E'V2 = 2 × 0.723 0.52 = 5.8 kgme'= 2 × E'V2 = 2 × 2.57 2.242 = 1.0 kgme'= 2 × E'V2 = 2 × 206.05 2.252 = 81.4 kg
    Tentative selection
    		Select Fixed Force Type
    Select Single Orifice from V
    Select MAKC1005 B from E' and me'

    (stroke
    S = 5 mm)
    		Select Adjustable Type
    Select Multi-Orifice from Fig. 2.
    Select MAC1210H from E' and me'

    (stroke
    S = 10 mm)
    		Select Adjustable Type
    Select Speed H Type from Fig. 2.
    Select MAC3650H from E' and me'

    (stroke
    S = 50 mm)
    Recalculation
    		E2 = E2’ = 0.098J
    E = E1+E2 = 0.723J    		me = 2 × EV2 = 5.8 kgE2 = 0.69J
    E = E1+E2 = 2.57J    		me = 1.0 kgE2=TR·S=2.74J
    E=E1+E2=206.05J    		me = 2 × E V2 = 81.4 kg
    Energy per minute ET
    		ET = E × N = 0.723 × 20 = 14.46 J/minET = E × N = 2.57 × 10 = 25.7 J/minET = E × N = 206.05 × 6 = 1,236.3 J/min
    Confirmation
    		E, me, N, and ET are all OK
    Select MAKC1005 B    		E, me, N, and ET are all OK
    Select MAC1210H    		E, me, N, and ET are all OK
    Select MAC3650H
    ■Shock Absorbers Classification according to absorption characteristics structures
    Structure
    Adjustable
    Fixed Force Type
    		 
    Tapered orifice
    S Type
    A Type
    B Type
    L Type
    		　There are three types of tapered orifices; a dashpot structure using a clearance between the piston and cylinder tube, a single-tube structure with an orifice in the piston, and a double-tube type tapered orifice, all of which exhibit similar drag force characteristics.
    　
    　
    　The piston slides in a cylinder tube filled with oil, and a tapered orifice is installed in this piston.
    Because the orifice area is constant over the entire stroke, as the shock absorption characteristics shown in the right graph, the resistance is the largest immediately after a collision but gradually reduces speed as the stroke continues.
    　
    　
    Irregular Multi
    Orifice
    Medium Speed
    Type M
    		　In this double-tube structure, the piston slides the
    inner wall of the inner tube. This inner tube has several orifices along the
    direction of strokes, and not constant damping, but
    absorbs energy depending on various purposes. It is designed to absorb kinetic energy during the first half of stroke and
    control speed during the second half. Therefore, it is well suited to
    absorb energy against air cylinder thrust.
    Multi
    Orifice
    High Speed
    Type H
    		　In this double-tube structure, the piston slides in the
    inner tube. This inner tube has several orifices along the direction
    of strokes. Because the orifice area
    becomes small gradually as the stroke speed slows down, the drag force fractures but the maximum drag is
    lower.
    [ ! ] Adjustable Type No.0806M is single orifice structure and No.3625 L Type is multi-orifice structure.
    * When using shock absorbers (fixed force type) in parallel, calculate the total energy as shown below.
    　　E = E'/n
    　　E: Energy acting on each shock absorber
    　　E’: Total Energy
    　　n: Number of shock absorber receivers
    * Do not use adjustable type shock absorbers in parallel.

    App. Example

    • The shock absorber cannot be used at full stroke.
      If used at full stroke, there is a possibility of damage.
    • Install so that the object stops at a distance of 1 mm or more from the stroke end, or install an external stopper as required.
      Stopper nuts also can be used.

    Cautions on Use

    ■ Precautions for Use
    • Shock absorbers use oil internally, and seals are used to prevent oil from leaking to the outside, but a perfect seal cannot be guaranteed.
      Because of this, it cannot be used in environments that prohibit oil.
    • Check for oil leaks and the return status of the piston rod. If leaking of a large amount of oil or failure of returning piston rod are found, there
      may be some abnormality and it should be replaced. If you use a defective product, it may cause damage to the unit to which it is installed.
    • With the number of uses, the energy absorption capacity will decrease due to the reduction in internal oil and wear of parts. Taking this into account, we recommend selecting a size that has
      at least 20 to 40% margin for the maximum absorbed energy.
    • The performance and functionality of shock absorbers may deteriorate depending on the load. Perform daily inspections to ensure that the required functions are met and to prevent accidents from occurring.

    Part number list

    Number of items
  • 1
    • Part number
    MAMKS1406
    MAMKS1606
    MAMKS2008
    MAMKS2508
    MAMKS2708

    Stroke

    (mm)

    Mounting Screw Nominal (M)

    Max. Absorbed Energy

    (J)

    Equivalent Mass

    (kgf)

    Max. Resisting Force Value

    (N)

    Piston Rod Return Force

    (N)

    Max. Absorbed Energy (per Minute)

    (J/min)

    Thread Size M

    		RoHS?Minimum order quantity
    6
    M14
    4.5
    80
    2000
    15
    100
    M14X1.5
    10
    1 pieces
    6
    M16
    5.5
    120
    2700
    20
    130
    M16X1.5
    10
    1 pieces
    8
    M20
    8.8
    70
    3430
    14.7
    200
    M20X1.5
    10
    1 pieces
    8
    M25
    13.7
    110
    5390
    21.6
    300
    M25X1.5
    10
    1 pieces
    8
    M27
    19.6
    150
    7350
    23.5
    350
    M27X1.5
    10
    1 pieces
    Unit price (excluding VAT)(Unit price including VAT)
    Standard shipping days
    68.01 €
    ( 80.93 € )
    Stock item: 1 working dayAvailable for same-day shipping
    69.27 €
    ( 82.43 € )
    5 working days
    69.27 €
    ( 82.43 € )
    5 working days
    81.87 €
    ( 97.43 € )
    5 working days
    88.16 €
    ( 104.91 € )
    5 working days
  • 1

    • More Information

    Basic information

    [Features] This is a more compact type than normal shock absorbers. It can be used in places where space is limited.